2n^2=-10-12

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Solution for 2n^2=-10-12 equation: 



2n^2=-10-12

We move all terms to the left:

2n^2-(-10-12)=0

We add all the numbers together, and all the variables

2n^2-(-22)=0

We add all the numbers together, and all the variables

2n^2+22=0

a = 2; b = 0; c = +22;
Δ = b2-4ac
Δ = 02-4·2·22
Δ = -176
Delta is less than zero, so there is no solution for the equation

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